The public theorem
The result
The Collatz conjecture predicts that every orbit reaches \(1\). This
paper does not prove that. It proves a quantitative almost-all
statement: outside a set of density zero, orbits come down to a
polylogarithmic value quickly, and the descent is witnessed by an
explicit clock.
Throughout, \(T\) is the shortcut Collatz map, \(T(n)=n/2\) for even
\(n\) and \(T(n)=(3n+1)/2\) for odd \(n\). Write \(H_2\) for binary
entropy and put
\[
\kappa_*=1-H_2(\log_3 2),
\qquad
A_{\rm FP}=\frac{1}{2\kappa_*},
\qquad
c_*=\frac{2}{\log(4/3)}.
\]
- Critical exponent
- 9.9911133419…
\(A_{\rm FP}\), the first-passage method threshold
- Shortcut clock
- 6.9521189935…
\(c_*\); any \(c>c_*\) is admissible
- Raw clock
- 10.4281784900…
\(3/\log(4/3)\) for the unaccelerated map
Main theorem
For every fixed \(A>A_{\rm FP}\), \(c>c_*\), \(\beta>0\), and
\(0<\gamma<\kappa_*(A-A_{\rm FP})\), there is
\(C_{\rm tar}>0\) such that, as \(X\to\infty\), all but
\(O_{A,c,\beta,\gamma}\!\left(X/(\log X)^{\gamma}\right)\) integers
\(n\le X\) admit an integer \(k<c\log n\) with
\[
T^k(n)\le C_{\rm tar}(\log n)^A,
\qquad
\max_{0\le j\le k}T^j(n)\le n^{1+\beta}.
\]
The same witness \(k\) carries all three conclusions at once: the
landing, the clock, and the ceiling on every earlier iterate. A moving
form allows the exponent to vary with the dyadic shell and reaches the
critical exponent itself, at the cost of explicit \(\log\log\) factors.
A stretched-logarithmic companion covers the weaker target
\(\exp((\log n)^{1-\delta})\) for every fixed \(0<\delta<1\).